Maths Boot Camp: Session 1
The Basics, Functions, and Logarithms
Your Instructor
- Dr. Marta Antonetti: m.antonetti@lse.ac.uk
- DPhil in Politics (Oxford)
- LSE Fellow (Dept. Government)
- Research Interests: Political Campaigns, Marginalisation and Equality, Epistemic Autonomy and Manipulation
- Experiments and Methods of Causal Inference
Setting Expectations
- Boot Camp is designed to be accessible
- From the basics to more challenging concepts
- Gives you an overview of what is to come
- No test
- Don’t feel frustrated by the volume of material!
- These sessions:
- 3 blocks (breaks)
- Group tasks
- Sessions 1 and 2 are preparatory
- I am also in charge of the pre-sessions on R programming
Support Textbooks
- Maths:
- Gill, J. (2006). Essential Mathematics for Political and Social Research.
- Moore, W. H., & Siegel, D. A. (2013). A mathematics course for political and social research.
- R:
- Llaudet, E., & Imai, K. (2022). Data analysis for social science.
- Imai, K. (2018). Quantitative Social Science.
- Package: swirl
- LSE Methodology Department: Methods surgeries available on Moodle
Session 1 Topics
- Numbers, Intervals, Sets
- Operators, Expressions, Equations, Inequalities
- Functions (Introduction, Inverse, Roots)
Block 1
Numbers, Intervals and Sets
Numbers
- Some Typology:
- N: Natural numbers \{1, 2, 3, \dots\}
- W: Whole numbers \{0, 1, 2, 3, \dots\}
- Z: Integers \{\dots, -2, -1, 0, 1, 2, \dots\}
- Q: Rational numbers \left(\frac{3}{5}\right)
- R: Real numbers, including irrational numbers \left(\pi, \sqrt{2}\right)
- C: Complex numbers z = 3 + 4i — real part 3, imaginary part 4, i the imaginary unit
Intervals
- \equiv “is equivalent to”; \in “belongs to”; : “such that”
- Open interval: (a,b) \equiv \{x \in \mathbb{R} : a < x < b\}
- Closed interval: [a,b] \equiv \{x \in \mathbb{R} : a \leq x \leq b\}
- Half open, half closed: (a,b] \equiv \{x \in \mathbb{R} : a < x \leq b\}
Sets
- Definition: a set is a collection of distinct objects
- Example: Set A = \{a, b, c\}, Set B = \{l, m, n, o\}
- Intersection: A \cap B = \varnothing
- Union: A \cup B = \{a, b, c, l, m, n, o\}
Sets
- Some Typology:
- Empty set: \varnothing or \{\}
- Universal set: The set of all elements in context.
- Complement: All elements not in the set A^c.
- Proper Subset: A \subset B
- Improper Subset: A \subseteq B
- Open set: \{x : -1 < x < 3, x \in \mathbb{R}\}
- Closed set: \{x : -1 \leq x \leq 3, x \in \mathbb{R}\}
Sets
- Boundary: A group of points that touch the complement of a set
- Interior Point: A point inside the boundary of a set
- Bounded Set: All points are within a certain finite space
- Unbounded Set: Points are not within a finite space, the set extends infinitely
- Compact Set: A set that is both closed and bounded
Sets — Your Turn
- Is it an open or a closed set?
- The set \{(x,y) \in \mathbb{R}^2 : |x+y| < 1 \}
- The set \{(x,y) \in \mathbb{R}^2 : x \leq 0, y \leq 0 \}
- Set of the faces of a dice (can you also tell me if it is bounded or unbounded?)
- The set \{(x,y) \in \mathbb{R}^2 : |x+y| < 1 \}: open
- The set \{(x,y) \in \mathbb{R}^2 : x \leq 0, y \leq 0 \}: closed
- Set of the number of a dice: bounded and closed, thus compact
Applied Example — Gill (2006)
Exploratory Study of Social Networks Using Sets
- 18 community members, 14 social events (A–N) — an “X” means that person attended that event
- Each event is a set of the people who attended it
- The more events two people share, the closer they are in the social network
Applied Example — Gill (2006)
Applied Example — Gill (2006)
- M = N: identical sets, both \{12, 13, 14\}
- Several disjoint pairs exist, e.g. \{A,J\}, \{B,L\}, \{D,M\}
- But the full collection A–N does not form a partition — too many overlapping intersections
- No subset of events forms a partition either — individuals 15–18 are the reason why
Quick Check — Numbers & Sets
- Classify each number as natural, integer, rational, and/or real: \left\{-3,\ \frac{5}{2},\ 4,\ \sqrt{2},\ 0\right\}
- Given A = \{1, 2, 3\} and B = \{3, 4, 5\}, find A \cup B, A \cap B, and A - B.
- -3: integer, rational, real | \frac{5}{2}: rational, real | 4: natural, integer, rational, real | \sqrt{2}: real (irrational) | 0: integer, rational, real
- A \cup B = \{1,2,3,4,5\}, A \cap B = \{3\}, A - B = \{1, 2\}
- A-B keeps only elements of A that are not in B — it doesn’t also add back what’s left of B, so it isn’t \{1,2,4,5\}; that combined set would be the symmetric difference, A \triangle B, a different operation
Towards the End of Block 1
Block 2
Operators, Expressions, Equations and Inequalities
Common Operators
- Addition + and Subtraction -: total, and difference, of numbers
- Multiplication \times: repeated addition
- Division : or /: splits a number into equal parts
Common Operators
- Power: a^b = c — multiplies a by itself b times to get c
- Root: \sqrt[b]{c} = a — what do you think this undoes? (c is exactly the power’s result — the number placed under the root)
- Finds the number a that, raised to the bth power, gives c
- Logarithm: \log_a c = b — what question is this secretly asking?
- Finds the exponent b to which a must be raised to produce c
- Summation: \sum_{i=1}^{n} a_i — any guesses?
- Adds a sequence of numbers
- Factorial: n! — and this one?
- Product of all positive integers up to n, e.g., n! = n \times (n-1) \times \dots \times 1
Properties of Powers
- Product of Powers: a^m \times a^n = a^{m+n}
- Quotient of Powers: \frac{a^m}{a^n} = a^{m-n}
- Power of a Power: (a^m)^n = a^{m \times n}
- Power of a Product: (a \times b)^n = a^n \times b^n
- Power of a Quotient: \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}
Properties of Powers — Quick Check
- Is (x \times y)^3 = x^3 \times y^3?
- Is a^3 \times a^3 = a^9?
- (x \times y)^3 = x^3 \times y^3? YES — power of a product
- a^3 \times a^3 = a^6, not a^9 — exponents add (3+3), they don’t multiply
Properties of Logarithms
- Product Rule: \log_a (b \cdot c) = \log_a b + \log_a c
- Quotient Rule: \log_a \left(\frac{b}{c}\right) = \log_a b - \log_a c
- Power Rule: \log_a (b^c) = c \cdot \log_a b
- Change of Base Formula: \log_a b = \frac{\log_c b}{\log_c a}
Properties of Logarithms — Quick Check
- Is \log_2 \left(\frac{3}{7}\right) = \log_2 3 - \log_2 7?
- Is \log_2 3 = \frac{\log_{10} 3}{\log_{10} 2}?
- \log_2 \left(\frac{3}{7}\right) = \log_2 3 - \log_2 7? YES — quotient rule
- \log_2 3 = \frac{\log_{10} 3}{\log_{10} 2}? YES — change of base formula
Order of Operations (PEMDAS)
- Parentheses: Operations inside parentheses first
- Exponents: Evaluate exponents next
- Multiplication and Division: Left to right
- Addition and Subtraction: Left to right
Expressions
- Combination of numbers, variables, and operators
- They denote a mathematical quantity (not an equality)
- Example: 3 + 4 \times 2 = ?
- According to PEMDAS: first the multiplication, 4 \times 2 = 8; then the addition, 3 + 8 = 11
- Thus, 3 + 4 \times 2 = 11
Expressions
- Example: Simplify the expression (2 + 3)^2
- According to PEMDAS: first evaluate inside the parentheses, 2 + 3 = 5; then the exponent, 5^2 = 25
- Thus, (2 + 3)^2 = 25
Equations
- Equation: states that two expressions are equal
- Solving means finding the x that makes it true
- Example: Solve 5x - 7 = 18
- Add 7 to both sides: 5x = 25
- Divide both sides by 5: x = 5
Equations
- Factorisation: express a polynomial as a product of factors
- Example: Factorise x^2 + 5x + 6
- Find two numbers multiplying to 6, summing to 5: 2 and 3
- x^2 + 5x + 6 = (x+2)(x+3), so x = -2 and x = -3
Equations
The quadratic formula is used to find the roots of a quadratic equation ax^2 + bx + c = 0. The formula is:
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
- a, b, and c are coefficients of the quadratic equation
Equations — Worked Example
Example: Solve 2x^2 - 4x - 6 = 0 using the quadratic formula
- Identify coefficients: a = 2, b = -4, c = -6
- Compute the discriminant: b^2 - 4ac = (-4)^2 - 4(2)(-6) = 16 + 48 = 64
- Substitute: x = \frac{-(-4) \pm \sqrt{64}}{2(2)} = \frac{4 \pm 8}{4}
- Solve: x = \frac{4+8}{4} = 3 and x = \frac{4-8}{4} = -1
- Thus, the solutions are x = 3 and x = -1
Inequalities
- Inequalities compare expressions: >, \geq, <, \leq
- Example: Solve 2x + 3 < 7
Inequalities — One More Rule
- Dividing by a negative number means you have to reverse the inequality sign
- Example: Solve -3x \geq 9
- Divide both sides by -3, remembering to reverse the inequality sign: \frac{-3x}{-3} \leq \frac{9}{-3}
- Simplify to x \leq -3
- Thus, the solution to -3x \geq 9 is x \leq -3
Quick Check — Logs & Equations
- Evaluate \log_2 8.
- Solve \log_5(x - 2) = 3.
- Solve x^2 - 4x - 5 = 0 by factoring.
- \log_2 8 = 3, since 2^3 = 8
- \log_5(x-2)=3 \Rightarrow x-2 = 5^3 = 125 \Rightarrow x = 127
- x^2-4x-5=(x-5)(x+1)=0 \Rightarrow x = 5 and x = -1
Towards the End of Block 2
Applied Example — Policy Preferences as Functions
- Before whole elections, start with something simpler: how much does one individual want a given policy?
- Picture a policy with a single intensity dial — e.g. how large a carbon tax should be, or how strict a sentencing guideline should be
- Each voter i has one preferred point on that dial, x_i — that’s already a function:
f(i) = x_i
- Voter in, preferred intensity out — one output per input
Functions
- Function: a “black-box” mapping, f(x): A \rightarrow B — domain A to co-domain B
- One output per input — the defining rule
- Different x can share the same y; one x with two y’s is a relation, not a function
Functions — Types
- Monomials: f(x) = ax^k; e.g. y = x^2
- Polynomials: sums of monomials; e.g. y = 3x + 5
- Rational: ratio of two polynomials; e.g. y = \frac{x^2+1}{2x^2-2x+1}
- Exponential: e.g. y = 2^x Trigonometric: e.g. y = \cos(x)
- Linear: polynomial of degree 1, e.g. y = mx+b Nonlinear: anything else
Roots of a Function
- A root of a function is a value x such that f(x) = 0
- Example: Find the root of the function f(x) = 2x^2 - 4x - 6
Roots of a Function
To find the roots of f(x) = 2x^2 - 4x - 6, solve 2x^2 - 4x - 6 = 0:
Step 1 — Identify the coefficients: a = 2, \quad b = -4, \quad c = -6
Step 2 — Use the quadratic formula: x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-6)}}{2(2)}
Step 3 — Simplify: b^2 - 4ac = 16 + 48 = 64, so x = \frac{4 \pm \sqrt{64}}{4}
Step 4 — Solve: \sqrt{64}=8, so x_1 = \frac{4+8}{4} = 3 and x_2 = \frac{4-8}{4} = -1
Solution: the roots of f(x) = 2x^2 - 4x - 6 are x = 3 and x = -1.
Composite Functions
- Composite functions are when the output of one function is used as the input of another, e.g. fg(x) or f[g(x)]
- Note that h[f(x)] is different from f[h(x)]
- Example: Given h(x) = x^2 and f(x) = x - 5: find h(f(2))
- Example: Given f(x) = 2x and g(x) = x+4: find f(g(x))
Composite Functions
- Given h(x) = x^2 and f(x) = x - 5:
- f(2) = 2 - 5 = -3
- h(f(2)) = h(-3) = (-3)^2 = 9
- Given f(x) = 2x and g(x) = x+4:
- f(g(x)) = 2(x+4) = 2x + 8
Quick Check — Functions
- Given f(x) = 2x^2 - 3x + 5, evaluate f(2).
- Find the roots of f(x) = x^2 - 5x + 6.
- f(2) = 2(2)^2 - 3(2) + 5 = 8 - 6 + 5 = 7
- x^2-5x+6=(x-2)(x-3)=0 \Rightarrow x = 2 and x = 3
Towards the End of Block 3
End of Session
- Next session:
- Scalars, Vectors
- Matrices
- Neighbourhoods, and Limits